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2019-01-28 閱讀量: 847
SQL SEVER如何計算地圖上兩點之間距離

問題描述:
table1

name? ?? ?? latitude? ?? ?? ?longitude

2112 W Peterson Ave? ?? ?? ?41.991178? ?? ???-87.683593

63rd St Beach? ?? ?? ?41.781016? ?? ???-87.57612

900 W Harrison St? ?? ??? 41.874675? ?? ???-87.650019

Aberdeen St & Jackson Blvd? ?? ??? 41.877726? ?? ???-87.654787

Aberdeen St & Monroe St? ?? ??? 41.880456? ?? ???-87.653929

Ada St & Washington Blvd? ?? ??? 41.88283? ?? ??? -87.661206

Adler Planetarium? ?? ??? 41.866095? ?? ???-87.607267

Albany Ave & 26th St? ?? ??? 41.844475? ?? ???-87.702013

Albany Ave & Bloomingdale Ave? ?? ???41.914027? ?? ???-87.705126

Artesian Ave & Hubbard St? ?? ??? 41.889492? ?? ???-87.688219

table2

from_station_name? ?? ??? to_station_name

Aberdeen St & Jackson Blvd? ?? ?? ?Aberdeen St & Monroe

Artesian Ave & Hubbard St? ?? ??? Ada St & Washington Blvd

根據(jù)table1的經(jīng)緯度計算table2兩點之間的距離應(yīng)該怎么操作?

解決方法:

select x.name,y.name , GEOGRAPHY::Point(x.latitude , x.longitude , 4326).STDistance(GEOGRAPHY::Point(y.latitude , y.longitude , 4326))

from table1 as x,table1 as y;

0.0000
4
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